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[utils] Support TTML without default namespace

In a strict sense such TTML is invalid, but Yahoo uses it.
Yen Chi Hsuan 10 лет назад
Родитель
Сommit
1b0427e6c4
2 измененных файлов с 21 добавлено и 3 удалено
  1. 15 0
      test/test_utils.py
  2. 6 3
      youtube_dl/utils.py

+ 15 - 0
test/test_utils.py

@@ -621,6 +621,21 @@ Line
 '''
         self.assertEqual(dfxp2srt(dfxp_data), srt_data)
 
+        dfxp_data_no_default_namespace = '''<?xml version="1.0" encoding="UTF-8"?>
+            <tt xml:lang="en" xmlns:tts="http://www.w3.org/ns/ttml#parameter">
+            <body>
+                <div xml:lang="en">
+                    <p begin="0" end="1">The first line</p>
+                </div>
+            </body>
+            </tt>'''
+        srt_data = '''1
+00:00:00,000 --> 00:00:01,000
+The first line
+
+'''
+        self.assertEqual(dfxp2srt(dfxp_data_no_default_namespace), srt_data)
+
 
 if __name__ == '__main__':
     unittest.main()

+ 6 - 3
youtube_dl/utils.py

@@ -1848,9 +1848,9 @@ def dfxp2srt(dfxp_data):
         out = str_or_empty(node.text)
 
         for child in node:
-            if child.tag == _x('ttml:br'):
+            if child.tag in (_x('ttml:br'), 'br'):
                 out += '\n' + str_or_empty(child.tail)
-            elif child.tag == _x('ttml:span'):
+            elif child.tag in (_x('ttml:span'), 'span'):
                 out += str_or_empty(parse_node(child))
             else:
                 out += str_or_empty(xml.etree.ElementTree.tostring(child))
@@ -1859,7 +1859,10 @@ def dfxp2srt(dfxp_data):
 
     dfxp = xml.etree.ElementTree.fromstring(dfxp_data.encode('utf-8'))
     out = []
-    paras = dfxp.findall(_x('.//ttml:p'))
+    paras = dfxp.findall(_x('.//ttml:p')) or dfxp.findall('.//p')
+
+    if not paras:
+        raise ValueError('Invalid dfxp/TTML subtitle')
 
     for para, index in zip(paras, itertools.count(1)):
         begin_time = parse_dfxp_time_expr(para.attrib['begin'])