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Эх сурвалжийг харах

Revert DLNA changes

DLNA has no fullscreen support - or rather it is _always_ in fullscreen
Tim Hobbs 11 жил өмнө
parent
commit
fc9c9a9848

+ 0 - 29
MediaBrowser.Dlna/PlayTo/Device.cs

@@ -30,15 +30,6 @@ namespace MediaBrowser.Dlna.PlayTo
             }
         }
 
-        private bool _fullscreen;
-        public bool IsFullscreen
-        {
-            get
-            {
-                return _fullscreen;
-            }
-        }
-
         private string _currentId = String.Empty;
         public string CurrentId
         {
@@ -216,26 +207,6 @@ namespace MediaBrowser.Dlna.PlayTo
             return SetVolume(tmp);
         }
 
-        public async Task<bool> ToggleFullscreen()
-        {
-            var command = RendererCommands.ServiceActions.FirstOrDefault(c => c.Name == "Fullscreen");
-            if (command == null)
-                return true;
-
-            var service = Properties.Services.FirstOrDefault(s => s.ServiceType == ServiceRenderingType);
-
-            if (service == null) {
-                throw new InvalidOperationException("Unable to find service");
-            }
-
-            _fullscreen = !_fullscreen;
-
-            var result = await new SsdpHttpClient(_httpClient, _config).SendCommandAsync(Properties.BaseUrl, service, command.Name, RendererCommands.BuildPost(command, service.ServiceType, _fullscreen))
-                .ConfigureAwait(false);
-
-            return true;
-        }
-
         public async Task<bool> SetVolume(int value)
         {
             var command = RendererCommands.ServiceActions.FirstOrDefault(c => c.Name == "SetVolume");

+ 0 - 3
MediaBrowser.Dlna/PlayTo/DlnaController.cs

@@ -283,9 +283,6 @@ namespace MediaBrowser.Dlna.PlayTo
                 case PlaystateCommand.PreviousTrack:
                     _currentItem = null;
                     return SetPrevious();
-
-                case PlaystateCommand.Fullscreen:
-                    return _device.ToggleFullscreen();
             }
 
             return Task.FromResult(true);